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〖1/1算式〗
    作业：求算式 2/3*14300*0.5/4*(sin(360*0.206)^3+300*3.142*0.44*(sin(360*0.206)+sin(360*(1.25-0.206*2))/3.14159)) 的值.
    题型：数学计算
    解:
          2/3*14300*0.5/4*(sin(360*0.206)^3+300*3.142*0.44*(sin(360*0.206)+sin(360*(1.25-0.206*2))/3.14159))
        =2/3*14300*0.5/4*(sin74.16^3+300*3.142*0.44*(sin(360*0.206)+sin(360*(1.25-0.206*2))/3.14159))
        =2/3*14300*0.5/4*(sin74.16^3+300*3.142*0.44*(sin74.16+sin(360*(1.25-0.206*2))/3.14159))
        =2/3*14300*0.5/4*(sin74.16^3+300*3.142*0.44*(sin74.16+sin(360*0.838)/3.14159))
        =2/3*14300*0.5/4*(sin74.16^3+300*3.142*0.44*(sin74.16+sin301.68/3.14159))
        =2/3*14300*0.5/4*(sin74.16^3+300*3.142*0.44*(-0.917515))
        =2/3*14300*0.5/4*(-381.378302)
        =0.666667*14300*0.5/4*(-381.378302)
        =9533.3381*0.5/4*(-381.378302)
        =4766.66905/4*(-381.378302)
        =1191.667263*(-381.378302)
        =(-454476.037312)
    答案:2/3*14300*0.5/4*(sin(360*0.206)^3+300*3.142*0.44*(sin(360*0.206)+sin(360*(1.25-0.206*2))/3.14159))=-454476.037312
    注：弧度制

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