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〖1/1算式〗
    作业：求算式 14300*3.14159/4*(1-(sin(0.206*360))/2/3.14159/0.206)*0.206+(3*0.206-1.25)*300*3.142 的值.
    题型：数学计算
    解:
          14300*3.14159/4*(1-(sin(0.206*360))/2/3.14159/0.206)*0.206+(3*0.206-1.25)*300*3.142
        =14300*3.14159/4*(1-(sin74.16)/2/3.14159/0.206)*0.206+(3*0.206-1.25)*300*3.142
        =14300*3.14159/4*(1-(-0.945206)/2/3.14159/0.206)*0.206+(3*0.206-1.25)*300*3.142
        =14300*3.14159/4*1.730262*0.206+(3*0.206-1.25)*300*3.142
        =14300*3.14159/4*1.730262*0.206+(-0.632)*300*3.142
        =44924.737/4*1.730262*0.206+(-0.632)*300*3.142
        =11231.18425*1.730262*0.206+(-0.632)*300*3.142
        =19432.891323*0.206+(-0.632)*300*3.142
        =4003.175613+(-0.632)*300*3.142
        =4003.175613+(-189.6)*3.142
        =4003.175613+(-595.7232)
        =3407.452413
    答案:14300*3.14159/4*(1-(sin(0.206*360))/2/3.14159/0.206)*0.206+(3*0.206-1.25)*300*3.142=3407.452413
    注：弧度制

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