总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 cos(4/5*π)+cos(8/5*π)+cos(12/5*π)+cos(16/5*π)+cos(20/5*π) 的值.
题型:数学计算
解:
cos(4/5*π)+cos(8/5*π)+cos(12/5*π)+cos(16/5*π)+cos(20/5*π)
=cos2.513274+cos(8/5*π)+cos(12/5*π)+cos(16/5*π)+cos(20/5*π)
=cos2.513274+cos5.026548+cos(12/5*π)+cos(16/5*π)+cos(20/5*π)
=cos2.513274+cos5.026548+cos7.539822+cos(16/5*π)+cos(20/5*π)
=cos2.513274+cos5.026548+cos7.539822+cos10.053096+cos(20/5*π)
=cos2.513274+cos5.026548+cos7.539822+cos10.053096+cos12.566371
=-0.809017+cos5.026548+cos7.539822+cos10.053096+cos12.566371
=-0.809017+0.309017+cos7.539822+cos10.053096+cos12.566371
=-0.809017+0.309017+0.309017+cos10.053096+cos12.566371
=-0.809017+0.309017+0.309017+-0.809017+cos12.566371
=-0.809017+0.309017+0.309017+-0.809017+1
=-0.5+0.309017+(-0.809017)+1
=-0.190983+(-0.809017)+1
=-1+1
=0 答案:cos(4/5*π)+cos(8/5*π)+cos(12/5*π)+cos(16/5*π)+cos(20/5*π)=0 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!