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〖1/1算式〗
    作业：求算式 6.9*10^(6)*(0.2/259+192.2*25*10^(-6)*205/352)^0.25*352^2*0.72*293/(273.15*259^5) 的值.
    题型：数学计算
    解:
          6.9*10^(6)*(0.2/259+192.2*25*10^(-6)*205/352)^0.25*352^2*0.72*293/(273.15*259^5)
        =6.9*10^6*(0.2/259+192.2*25*10^(-6)*205/352)^0.25*352^2*0.72*293/(273.15*259^5)
        =6.9*10^6*(0.2/259+192.2*25*10^(-6)*205/352)^0.25*352^2*0.72*293/(273.15*259^5)
        =6.9*10^6*0.00357^0.25*352^2*0.72*293/(273.15*259^5)
        =6.9*10^6*0.00357^0.25*352^2*0.72*293/318346460269421.8125
        =6.9*1000000*0.00357^0.25*352^2*0.72*293/318346460269421.8125
        =6.9*1000000*0.24443706139855*352^2*0.72*293/318346460269421.8125
        =6.9*1000000*0.24443706139855*123904*0.72*293/318346460269421.8125
        =6900000*0.24443706139855*123904*0.72*293/318346460269421.8125
        =1686615.72365*123904*0.72*293/318346460269421.8125
        =208978434623.129608*0.72*293/318346460269421.8125
        =150464472928.65332*293/318346460269421.8125
        =44086090568095.421875/318346460269421.8125
        =0.138485
    答案:6.9*10^(6)*(0.2/259+192.2*25*10^(-6)*205/352)^0.25*352^2*0.72*293/(273.15*259^5)=0.138485

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