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〖1/1算式〗
作业:求算式 2+(0.589*(2.3*10^10)^0.25/(1+(0.469/0.7296)^(9/16))^(4/9)) 的值.
题型:数学计算
解:
2+(0.589*(2.3*10^10)^0.25/(1+(0.469/0.7296)^(9/16))^(4/9))
=2+(0.589*23000000000^0.25/(1+(0.469/0.7296)^(9/16))^(4/9))
=2+(0.589*23000000000^0.25/(1+0.642818^(9/16))^(4/9))
=2+(0.589*23000000000^0.25/(1+0.642818^0.5625)^(4/9))
=2+(0.589*23000000000^0.25/1.779919^(4/9))
=2+(0.589*23000000000^0.25/1.779919^0.444444)
=2+177.524529
=179.524529 答案:2+(0.589*(2.3*10^10)^0.25/(1+(0.469/0.7296)^(9/16))^(4/9))=179.524529你的问题在这里没有得到解决?请到 热门难题 里面看看吧!