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☆算术计算1题
〖1/1算式〗
作业:求算式 (4*e^(-0.1*0.25))+(4*e^(-0.105*0.75))+(104*e^(-0.11*1.25)) 的值.
题型:数学计算
解:
(4*e^(-0.1*0.25))+(4*e^(-0.105*0.75))+(104*e^(-0.11*1.25))
=(4*e^(-0.025))+(4*e^(-0.105*0.75))+(104*e^(-0.11*1.25))
=3.90124+(4*e^(-0.105*0.75))+(104*e^(-0.11*1.25))
=3.90124+(4*e^(-0.07875))+(104*e^(-0.11*1.25))
=3.90124+3.697084+(104*e^(-0.11*1.25))
=3.90124+3.697084+(104*e^(-0.1375))
=3.90124+3.697084+90.639572
=7.598324+90.639572
=98.237896 答案:(4*e^(-0.1*0.25))+(4*e^(-0.105*0.75))+(104*e^(-0.11*1.25))=98.237896你的问题在这里没有得到解决?请到 热门难题 里面看看吧!