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〖1/1算式〗
作业:求算式 (1-0.058*ln2485.7)*270000*599.8^2*2485.7/(7884.2*(2485.7^2+599.8^2)^1.5) 的值.
题型:数学计算
解:
(1-0.058*ln2485.7)*270000*599.8^2*2485.7/(7884.2*(2485.7^2+599.8^2)^1.5)
=0.546538*270000*599.8^2*2485.7/(7884.2*(2485.7^2+599.8^2)^1.5)
=0.546538*270000*599.8^2*2485.7/(7884.2*6538464.53^1.5)
=0.546538*270000*599.8^2*2485.7/131816959740539.125
=0.546538*270000*359760.039999999920838*2485.7/131816959740539.125
=147565.26*359760.039999999920838*2485.7/131816959740539.125
=53088083840.210388*2485.7/131816959740539.125
=131961050001610.953125/131816959740539.125
=1.001093 答案:(1-0.058*ln2485.7)*270000*599.8^2*2485.7/(7884.2*(2485.7^2+599.8^2)^1.5)=1.001093你的问题在这里没有得到解决?请到 热门难题 里面看看吧!