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〖1/1算式〗
    作业：求算式 2*500/sqrt(3)*ln(0.05/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1) 的值.
    题型：数学计算
    解:
          2*500/sqrt(3)*ln(0.05/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
        =2*500/sqrt3*ln(0.05/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
        =2*500/sqrt3*ln1-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
        =2*500/sqrt3*ln1-300+300*0.05^2/0.0075*(0.1^2/0.05^2-1)
        =2*500/sqrt3*ln1-300+300*0.05^2/0.0075*3
        =2*500/1.732051*ln1-300+300*0.05^2/0.0075*3
        =2*500/1.732051*0-300+300*0.05^2/0.0075*3
        =2*500/1.732051*0-300+300*0.0025/0.0075*3
        =1000/1.732051*0-300+300*0.0025/0.0075*3
        =577.350205*0-300+300*0.0025/0.0075*3
        =0-300+300*0.0025/0.0075*3
        =0-300+0.75/0.0075*3
        =0-300+100*3
        =0-300+300
        =-300+300
        =0
    答案:2*500/sqrt(3)*ln(0.05/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)=0

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