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〖1/1算式〗
    作业：求算式 (24*0.22)/2*(2/3*0.22)+((36.67+59.55)*3.1)/2*(2/3*3.1*(2*36.67+59.55)/(36.67+59.55)+1.1) 的值.
    题型：数学计算
    解:
          (24*0.22)/2*(2/3*0.22)+((36.67+59.55)*3.1)/2*(2/3*3.1*(2*36.67+59.55)/(36.67+59.55)+1.1)
        =5.28/2*(2/3*0.22)+((36.67+59.55)*3.1)/2*(2/3*3.1*(2*36.67+59.55)/(36.67+59.55)+1.1)
        =5.28/2*0.146667+((36.67+59.55)*3.1)/2*(2/3*3.1*(2*36.67+59.55)/(36.67+59.55)+1.1)
        =5.28/2*0.146667+(96.22*3.1)/2*(2/3*3.1*(2*36.67+59.55)/(36.67+59.55)+1.1)
        =5.28/2*0.146667+298.282/2*(2/3*3.1*(2*36.67+59.55)/(36.67+59.55)+1.1)
        =5.28/2*0.146667+298.282/2*(2/3*3.1*132.89/(36.67+59.55)+1.1)
        =5.28/2*0.146667+298.282/2*(2/3*3.1*132.89/96.22+1.1)
        =5.28/2*0.146667+298.282/2*3.954287
        =2.64*0.146667+298.282/2*3.954287
        =0.387201+298.282/2*3.954287
        =0.387201+149.141*3.954287
        =0.387201+589.746317
        =590.133518
    答案:(24*0.22)/2*(2/3*0.22)+((36.67+59.55)*3.1)/2*(2/3*3.1*(2*36.67+59.55)/(36.67+59.55)+1.1)=590.133518

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