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〖1/1算式〗
作业:求算式 (10^(-7)*(24.6^2-2.77^2))/52+(10^(-10)*(24.6-2.77)*7.5)/0.8 的值.
题型:数学计算
解:
(10^(-7)*(24.6^2-2.77^2))/52+(10^(-10)*(24.6-2.77)*7.5)/0.8
=(10^(-7)*(24.6^2-2.77^2))/52+(10^(-10)*(24.6-2.77)*7.5)/0.8
=(10^-7*597.4871)/52+(10^(-10)*(24.6-2.77)*7.5)/0.8
=0.00006/52+(10^(-10)*(24.6-2.77)*7.5)/0.8
=0.00006/52+(10^(-10)*(24.6-2.77)*7.5)/0.8
=0.00006/52+(10^-10*21.83*7.5)/0.8
=0.00006/52+0/0.8
=0.000001+0/0.8
=0.000001+0
=0.000001 答案:(10^(-7)*(24.6^2-2.77^2))/52+(10^(-10)*(24.6-2.77)*7.5)/0.8=0.000001你的问题在这里没有得到解决?请到 热门难题 里面看看吧!