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〖1/1算式〗
作业:求算式 (10^(-7)*(66^2-5.52^2))/52+(10^(-10)*(66-5.52)*7.5)/0.8 的值.
题型:数学计算
解:
(10^(-7)*(66^2-5.52^2))/52+(10^(-10)*(66-5.52)*7.5)/0.8
=(10^(-7)*(66^2-5.52^2))/52+(10^(-10)*(66-5.52)*7.5)/0.8
=(10^-7*4325.5296)/52+(10^(-10)*(66-5.52)*7.5)/0.8
=0.000433/52+(10^(-10)*(66-5.52)*7.5)/0.8
=0.000433/52+(10^(-10)*(66-5.52)*7.5)/0.8
=0.000433/52+(10^-10*60.48*7.5)/0.8
=0.000433/52+0/0.8
=0.000008+0/0.8
=0.000008+0
=0.000008 答案:(10^(-7)*(66^2-5.52^2))/52+(10^(-10)*(66-5.52)*7.5)/0.8=0.000008你的问题在这里没有得到解决?请到 热门难题 里面看看吧!