总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 20000÷(1+10%)^1+36000÷(1+10%)^2-(15000+10000÷(1+10%)^0.5+10000÷(1+10%)^1.5) 的值.
题型:数学计算
解:
20000÷(1+10%)^1+36000÷(1+10%)^2-(15000+10000÷(1+10%)^0.5+10000÷(1+10%)^1.5)
=20000÷1.1^1+36000÷(1+10%)^2-(15000+10000÷(1+10%)^0.5+10000÷(1+10%)^1.5)
=20000÷1.1^1+36000÷1.1^2-(15000+10000÷(1+10%)^0.5+10000÷(1+10%)^1.5)
=20000÷1.1^1+36000÷1.1^2-(15000+10000÷1.1^0.5+10000÷(1+10%)^1.5)
=20000÷1.1^1+36000÷1.1^2-(15000+10000÷1.1^0.5+10000÷1.1^1.5)
=20000÷1.1^1+36000÷1.1^2-33202.467612
=20000÷1.1+36000÷1.1^2-33202.467612
=20000÷1.1+36000÷1.21-33202.467612
=18181.818182+36000÷1.21-33202.467612
=18181.818182+29752.066116-33202.467612
=47933.884298-33202.467612
=14731.416686 答案:20000÷(1+10%)^1+36000÷(1+10%)^2-(15000+10000÷(1+10%)^0.5+10000÷(1+10%)^1.5)=14731.416686你的问题在这里没有得到解决?请到 热门难题 里面看看吧!