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〖1/1算式〗
作业:求算式 2*500*0.087^2/(sqrt(3)*0.1^2)-390*0.05^2/(0.1^2-0.05^2)*2 的值.
题型:数学计算
解:
2*500*0.087^2/(sqrt(3)*0.1^2)-390*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.087^2/(sqrt3*0.1^2)-390*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.087^2/0.017321-390*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.087^2/0.017321-390*0.05^2/0.0075*2
=2*500*0.007569/0.017321-390*0.05^2/0.0075*2
=2*500*0.007569/0.017321-390*0.0025/0.0075*2
=1000*0.007569/0.017321-390*0.0025/0.0075*2
=7.569/0.017321-390*0.0025/0.0075*2
=436.984008-390*0.0025/0.0075*2
=436.984008-0.975/0.0075*2
=436.984008-130*2
=436.984008-260
=176.984008 答案:2*500*0.087^2/(sqrt(3)*0.1^2)-390*0.05^2/(0.1^2-0.05^2)*2=176.984008你的问题在这里没有得到解决?请到 热门难题 里面看看吧!