总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 2*500*0.0781^2/(sqrt(3)*0.1^2)-370*0.05^2/(0.1^2-0.05^2)*2 的值.
题型:数学计算
解:
2*500*0.0781^2/(sqrt(3)*0.1^2)-370*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0781^2/(sqrt3*0.1^2)-370*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0781^2/0.017321-370*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0781^2/0.017321-370*0.05^2/0.0075*2
=2*500*0.00609961/0.017321-370*0.05^2/0.0075*2
=2*500*0.00609961/0.017321-370*0.0025/0.0075*2
=1000*0.00609961/0.017321-370*0.0025/0.0075*2
=6.09961/0.017321-370*0.0025/0.0075*2
=352.151146-370*0.0025/0.0075*2
=352.151146-0.925/0.0075*2
=352.151146-123.333333*2
=352.151146-246.666666
=105.48448 答案:2*500*0.0781^2/(sqrt(3)*0.1^2)-370*0.05^2/(0.1^2-0.05^2)*2=105.48448你的问题在这里没有得到解决?请到 热门难题 里面看看吧!