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作业:求算式 2*500*0.0721^2/(sqrt(3)*0.1^2)-350*0.05^2/(0.1^2-0.05^2)*2 的值.
题型:数学计算
解:
2*500*0.0721^2/(sqrt(3)*0.1^2)-350*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0721^2/(sqrt3*0.1^2)-350*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0721^2/0.017321-350*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0721^2/0.017321-350*0.05^2/0.0075*2
=2*500*0.00519841/0.017321-350*0.05^2/0.0075*2
=2*500*0.00519841/0.017321-350*0.0025/0.0075*2
=1000*0.00519841/0.017321-350*0.0025/0.0075*2
=5.19841/0.017321-350*0.0025/0.0075*2
=300.121817-350*0.0025/0.0075*2
=300.121817-0.875/0.0075*2
=300.121817-116.666667*2
=300.121817-233.333334
=66.788483 答案:2*500*0.0721^2/(sqrt(3)*0.1^2)-350*0.05^2/(0.1^2-0.05^2)*2=66.788483你的问题在这里没有得到解决?请到 热门难题 里面看看吧!