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作业:求算式 2*500*0.0674^2/(sqrt(3)*0.1^2)-330*0.05^2/(0.1^2-0.05^2)*2 的值.
题型:数学计算
解:
2*500*0.0674^2/(sqrt(3)*0.1^2)-330*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0674^2/(sqrt3*0.1^2)-330*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0674^2/0.017321-330*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0674^2/0.017321-330*0.05^2/0.0075*2
=2*500*0.00454276/0.017321-330*0.05^2/0.0075*2
=2*500*0.00454276/0.017321-330*0.0025/0.0075*2
=1000*0.00454276/0.017321-330*0.0025/0.0075*2
=4.54276/0.017321-330*0.0025/0.0075*2
=262.268922-330*0.0025/0.0075*2
=262.268922-0.825/0.0075*2
=262.268922-110*2
=262.268922-220
=42.268922 答案:2*500*0.0674^2/(sqrt(3)*0.1^2)-330*0.05^2/(0.1^2-0.05^2)*2=42.268922你的问题在这里没有得到解决?请到 热门难题 里面看看吧!