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〖1/1算式〗
作业:求算式 2*500*0.0635^2/(sqrt(3)*0.1^2)-310*0.05^2/(0.1^2-0.05^2)*2 的值.
题型:数学计算
解:
2*500*0.0635^2/(sqrt(3)*0.1^2)-310*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0635^2/(sqrt3*0.1^2)-310*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0635^2/0.017321-310*0.05^2/(0.1^2-0.05^2)*2
=2*500*0.0635^2/0.017321-310*0.05^2/0.0075*2
=2*500*0.00403225/0.017321-310*0.05^2/0.0075*2
=2*500*0.00403225/0.017321-310*0.0025/0.0075*2
=1000*0.00403225/0.017321-310*0.0025/0.0075*2
=4.03225/0.017321-310*0.0025/0.0075*2
=232.795451-310*0.0025/0.0075*2
=232.795451-0.775/0.0075*2
=232.795451-103.333333*2
=232.795451-206.666666
=26.128785 答案:2*500*0.0635^2/(sqrt(3)*0.1^2)-310*0.05^2/(0.1^2-0.05^2)*2=26.128785你的问题在这里没有得到解决?请到 热门难题 里面看看吧!