总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 2*500/sqrt(3)-330-330*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1) 的值.
题型:数学计算
解:
2*500/sqrt(3)-330-330*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1)
=2*500/sqrt3-330-330*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1)
=2*500/sqrt3-330-330*0.05^2/0.0075*((0.1^2/0.05^2)+1)
=2*500/sqrt3-330-330*0.05^2/0.0075*(4+1)
=2*500/sqrt3-330-330*0.05^2/0.0075*5
=2*500/1.732051-330-330*0.05^2/0.0075*5
=2*500/1.732051-330-330*0.0025/0.0075*5
=1000/1.732051-330-330*0.0025/0.0075*5
=577.350205-330-330*0.0025/0.0075*5
=577.350205-330-0.825/0.0075*5
=577.350205-330-110*5
=577.350205-330-550
=247.350205-550
=-302.649795 答案:2*500/sqrt(3)-330-330*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1)=-302.649795你的问题在这里没有得到解决?请到 热门难题 里面看看吧!