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作业:求算式 2/sqrt(3)*500*ln(0.0635/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.0635^2-1) 的值.
题型:数学计算
解:
2/sqrt(3)*500*ln(0.0635/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.0635^2-1)
=2/sqrt3*500*ln(0.0635/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.0635^2-1)
=2/sqrt3*500*ln1.27-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.0635^2-1)
=2/sqrt3*500*ln1.27-300+300*0.05^2/0.0075*(0.1^2/0.0635^2-1)
=2/sqrt3*500*ln1.27-300+300*0.05^2/0.0075*1.480005
=2/1.732051*500*ln1.27-300+300*0.05^2/0.0075*1.480005
=2/1.732051*500*0.239017-300+300*0.05^2/0.0075*1.480005
=2/1.732051*500*0.239017-300+300*0.0025/0.0075*1.480005
=1.1547*500*0.239017-300+300*0.0025/0.0075*1.480005
=577.35*0.239017-300+300*0.0025/0.0075*1.480005
=137.996465-300+300*0.0025/0.0075*1.480005
=137.996465-300+0.75/0.0075*1.480005
=137.996465-300+100*1.480005
=137.996465-300+148.0005
=-162.003535+148.0005
=-14.003035 答案:2/sqrt(3)*500*ln(0.0635/0.05)-300+300*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.0635^2-1)=-14.003035你的问题在这里没有得到解决?请到 热门难题 里面看看吧!