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☆算术计算1题
〖1/1算式〗
作业:求算式 -99+52/1.113+40/(1.113^2)+31/(1.113^3)+20/(1.113^4) 的值.
题型:数学计算
解:
-99+52/1.113+40/(1.113^2)+31/(1.113^3)+20/(1.113^4)
=-99+52/1.113+40/1.238769+31/(1.113^3)+20/(1.113^4)
=-99+52/1.113+40/1.238769+31/1.378749897+20/(1.113^4)
=-99+52/1.113+40/1.238769+31/1.378749897+20/1.534548635361
=-99+46.720575+40/1.238769+31/1.378749897+20/1.534548635361
=-99+46.720575+32.29012+31/1.378749897+20/1.534548635361
=-99+46.720575+32.29012+22.484136+20/1.534548635361
=-99+46.720575+32.29012+22.484136+13.033148
=-52.279425+32.29012+22.484136+13.033148
=-19.989305+22.484136+13.033148
=2.494831+13.033148
=15.527979 答案:-99+52/1.113+40/(1.113^2)+31/(1.113^3)+20/(1.113^4)=15.527979你的问题在这里没有得到解决?请到 热门难题 里面看看吧!