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☆算术计算1题
〖1/1算式〗
作业:求算式 -99+25/1.113+31/(1.113^2)+40/(1.113^3)+52/(1.113^4) 的值.
题型:数学计算
解:
-99+25/1.113+31/(1.113^2)+40/(1.113^3)+52/(1.113^4)
=-99+25/1.113+31/1.238769+40/(1.113^3)+52/(1.113^4)
=-99+25/1.113+31/1.238769+40/1.378749897+52/(1.113^4)
=-99+25/1.113+31/1.238769+40/1.378749897+52/1.534548635361
=-99+22.461815+31/1.238769+40/1.378749897+52/1.534548635361
=-99+22.461815+25.024843+40/1.378749897+52/1.534548635361
=-99+22.461815+25.024843+29.011788+52/1.534548635361
=-99+22.461815+25.024843+29.011788+33.886186
=-76.538185+25.024843+29.011788+33.886186
=-51.513342+29.011788+33.886186
=-22.501554+33.886186
=11.384632 答案:-99+25/1.113+31/(1.113^2)+40/(1.113^3)+52/(1.113^4)=11.384632你的问题在这里没有得到解决?请到 热门难题 里面看看吧!