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〖1/1算式〗
作业:求算式 -99+23/1.112+30/(1.112^2)+40/(1.112^3)+50/(1.112^4) 的值.
题型:数学计算
解:
-99+23/1.112+30/(1.112^2)+40/(1.112^3)+50/(1.112^4)
=-99+23/1.112+30/1.236544+40/(1.112^3)+50/(1.112^4)
=-99+23/1.112+30/1.236544+40/1.375036928+50/(1.112^4)
=-99+23/1.112+30/1.236544+40/1.375036928+50/1.529041063936001
=-99+20.683453+30/1.236544+40/1.375036928+50/1.529041063936001
=-99+20.683453+24.261167+40/1.375036928+50/1.529041063936001
=-99+20.683453+24.261167+29.090128+50/1.529041063936001
=-99+20.683453+24.261167+29.090128+32.700234
=-78.316547+24.261167+29.090128+32.700234
=-54.05538+29.090128+32.700234
=-24.965252+32.700234
=7.734982 答案:-99+23/1.112+30/(1.112^2)+40/(1.112^3)+50/(1.112^4)=7.734982你的问题在这里没有得到解决?请到 热门难题 里面看看吧!