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〖1/1算式〗
作业:求算式 1-e(-1*0.531)*cos((35)^0.5*0.531)+((35^0.5)/35)*sin((35)^0.5*0.531) 的值.
题型:数学计算
解:
1-e(-1*0.531)*cos((35)^0.5*0.531)+((35^0.5)/35)*sin((35)^0.5*0.531)
=1-e(-0.531)*cos((35)^0.5*0.531)+((35^0.5)/35)*sin((35)^0.5*0.531)
=1-e-0.531*cos(35^0.5*0.531)+((35^0.5)/35)*sin((35)^0.5*0.531)
=1-e-0.531*cos3.141438+((35^0.5)/35)*sin((35)^0.5*0.531)
=1-e-0.531*cos3.141438+(5.916079783099616/35)*sin((35)^0.5*0.531)
=1-e-0.531*cos3.141438+0.169031*sin((35)^0.5*0.531)
=1-e-0.531*cos3.141438+0.169031*sin(35^0.5*0.531)
=1-e-0.531*cos3.141438+0.169031*sin3.141438
=1-0.588017*cos3.141438+0.169031*sin3.141438
=1-0.588017*-1+0.169031*sin3.141438
=1-0.588017*-1+0.169031*0.000155
=1-(-0.588017)+0.169031*0.000155
=1--0.588017+0.000026
=1.588017+0.000026
=1.588043 答案:1-e(-1*0.531)*cos((35)^0.5*0.531)+((35^0.5)/35)*sin((35)^0.5*0.531)=1.588043 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!