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作业:求算式 (8.5-tan30)*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5 的值.
题型:数学计算
解:
(8.5-tan30)*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5
=14.905331*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5
=14.905331*sin34.47/sin(45+21.06/2+30)+1/cos30+1.5
=14.905331*sin34.47/sin85.53+1/cos30+1.5
=14.905331*0.087408/sin85.53+1/cos30+1.5
=14.905331*0.087408/-0.649555+1/cos30+1.5
=14.905331*0.087408/-0.649555+1/0.154251+1.5
=1.302845/(-0.649555)+1/0.154251+1.5
=(-2.00575)+1/0.154251+1.5
=-2.00575+6.48294+1.5
=4.47719+1.5
=5.97719 答案:(8.5-tan30)*sin(45-21.06/2)/sin(45+21.06/2+30)+1/cos30+1.5=5.97719 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!