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〖1/1算式〗
    作业：求算式 -(450/800)*log(2,450/800)-(300/800)*log(2,300/800)-(50/800)*log(2,50/800) 的值.
    题型：数学计算
    解:
          -(450/800)*log(2,450/800)-(300/800)*log(2,300/800)-(50/800)*log(2,50/800)
        =-0.5625*log(2,450/800)-(300/800)*log(2,300/800)-(50/800)*log(2,50/800)
        =-0.5625*(-0.830075)-(300/800)*log(2,300/800)-(50/800)*log(2,50/800)
        =-0.5625*(-0.830075)-0.375*log(2,300/800)-(50/800)*log(2,50/800)
        =-0.5625*(-0.830075)-0.375*(-1.415037)-(50/800)*log(2,50/800)
        =-0.5625*(-0.830075)-0.375*(-1.415037)-0.0625*log(2,50/800)
        =-0.5625*(-0.830075)-0.375*(-1.415037)-0.0625*(-4)
        =0.466917-0.375*(-1.415037)-0.0625*(-4)
        =0.466917-(-0.530639)-0.0625*(-4)
        =0.466917--0.530639-(-0.25)
        =0.997556-(-0.25)
        =1.247556
    答案:-(450/800)*log(2,450/800)-(300/800)*log(2,300/800)-(50/800)*log(2,50/800)=1.247556

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