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〖1/1算式〗
作业:求算式 -(150/350)*log(2,150/350)-(150/350)*log(2,150/350)-(50/350)*log(2,50/350) 的值.
题型:数学计算
解:
-(150/350)*log(2,150/350)-(150/350)*log(2,150/350)-(50/350)*log(2,50/350)
=-0.428571*log(2,150/350)-(150/350)*log(2,150/350)-(50/350)*log(2,50/350)
=-0.428571*(-1.222394)-(150/350)*log(2,150/350)-(50/350)*log(2,50/350)
=-0.428571*(-1.222394)-0.428571*log(2,150/350)-(50/350)*log(2,50/350)
=-0.428571*(-1.222394)-0.428571*(-1.222394)-(50/350)*log(2,50/350)
=-0.428571*(-1.222394)-0.428571*(-1.222394)-0.142857*log(2,50/350)
=-0.428571*(-1.222394)-0.428571*(-1.222394)-0.142857*(-2.807356)
=0.523883-0.428571*(-1.222394)-0.142857*(-2.807356)
=0.523883-(-0.523883)-0.142857*(-2.807356)
=0.523883--0.523883-(-0.40105)
=1.047766-(-0.40105)
=1.448816 答案:-(150/350)*log(2,150/350)-(150/350)*log(2,150/350)-(50/350)*log(2,50/350)=1.448816你的问题在这里没有得到解决?请到 热门难题 里面看看吧!