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〖1/1算式〗
    作业：求算式 1400.51*(sin0.42*3.14)^3/3.14+360000*0.004022*0.342*((sin0.42*3.14)+sin0.41*3.14)/3.14 的值.
    题型：数学计算
    解:
          1400.51*(sin0.42*3.14)^3/3.14+360000*0.004022*0.342*((sin0.42*3.14)+sin0.41*3.14)/3.14
        =1400.51*1.280366^3/3.14+360000*0.004022*0.342*((sin0.42*3.14)+sin0.41*3.14)/3.14
        =1400.51*1.280366^3/3.14+360000*0.004022*0.342*(1.280366+sin0.41*3.14)/3.14
        =1400.51*1.280366^3/3.14+360000*0.004022*0.342*2.531998/3.14
        =1400.51*2.098951477640068/3.14+360000*0.004022*0.342*2.531998/3.14
        =2939.602534/3.14+360000*0.004022*0.342*2.531998/3.14
        =936.179151+360000*0.004022*0.342*2.531998/3.14
        =936.179151+1447.92*0.342*2.531998/3.14
        =936.179151+495.18864*2.531998/3.14
        =936.179151+1253.816646/3.14
        =936.179151+399.304664
        =1335.483815
    答案:1400.51*(sin0.42*3.14)^3/3.14+360000*0.004022*0.342*((sin0.42*3.14)+sin0.41*3.14)/3.14=1335.483815
    注：弧度制

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