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〖1/1算式〗
    作业：求算式 10*((1.25*0.103)^2+1)^(0.5)/((1.25*0.2)^2+1)^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25 的值.
    题型：数学计算
    解:
          10*((1.25*0.103)^2+1)^(0.5)/((1.25*0.2)^2+1)^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*(0.12875^2+1)^(0.5)/((1.25*0.2)^2+1)^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^(0.5)/((1.25*0.2)^2+1)^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/((1.25*0.2)^2+1)^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/(0.25^2+1)^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/1.0625^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/1.0625^0.5/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/1.0625^0.5/(0.625^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/1.0625^0.5/1.390625^(0.5)/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/1.0625^0.5/1.390625^0.5/((1.25)^2+1)^(0.5)/1.25
        =10*1.016577^0.5/1.0625^0.5/1.390625^0.5/(1.25^2+1)^(0.5)/1.25
        =10*1.016577^0.5/1.0625^0.5/1.390625^0.5/2.5625^(0.5)/1.25
        =10*1.016577^0.5/1.0625^0.5/1.390625^0.5/2.5625^0.5/1.25
        =10*1.008254432174736/1.0625^0.5/1.390625^0.5/2.5625^0.5/1.25
        =10*1.008254432174736/1.030776406404415/1.390625^0.5/2.5625^0.5/1.25
        =10*1.008254432174736/1.030776406404415/1.179247641507075/2.5625^0.5/1.25
        =10*1.008254432174736/1.030776406404415/1.179247641507075/1.600781059358212/1.25
        =10.082544/1.030776406404415/1.179247641507075/1.600781059358212/1.25
        =9.781504/1.179247641507075/1.600781059358212/1.25
        =8.294699/1.600781059358212/1.25
        =5.181657/1.25
        =4.145326
    答案:10*((1.25*0.103)^2+1)^(0.5)/((1.25*0.2)^2+1)^(0.5)/((1.25*0.5)^2+1)^(0.5)/((1.25)^2+1)^(0.5)/1.25=4.145326

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