本次共计算 1 个题目:每一题对 x 求 4 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数\frac{-3}{2}cos(2x + 1 + 8lg(2x + 1)) 关于 x 的 4 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = \frac{-3}{2}cos(2x + 8lg(2x + 1) + 1)\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( \frac{-3}{2}cos(2x + 8lg(2x + 1) + 1)\right)}{dx}\\=&\frac{-3}{2}*-sin(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)\\=&3sin(2x + 8lg(2x + 1) + 1) + \frac{24sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln{10}}\\\\ &\color{blue}{函数的第 2 阶导数:} \\&\frac{d\left( 3sin(2x + 8lg(2x + 1) + 1) + \frac{24sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln{10}}\right)}{dx}\\=&3cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0) + \frac{24(\frac{-(2 + 0)}{(2x + 1)^{2}})sin(2x + 8lg(2x + 1) + 1)}{ln{10}} + \frac{24*-0sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln^{2}{10}} + \frac{24cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)ln{10}}\\=&6cos(2x + 8lg(2x + 1) + 1) + \frac{96cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln{10}} - \frac{48sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln{10}} + \frac{384cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{2}{10}}\\\\ &\color{blue}{函数的第 3 阶导数:} \\&\frac{d\left( 6cos(2x + 8lg(2x + 1) + 1) + \frac{96cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln{10}} - \frac{48sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln{10}} + \frac{384cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{2}{10}}\right)}{dx}\\=&6*-sin(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0) + \frac{96(\frac{-(2 + 0)}{(2x + 1)^{2}})cos(2x + 8lg(2x + 1) + 1)}{ln{10}} + \frac{96*-0cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln^{2}{10}} + \frac{96*-sin(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)ln{10}} - \frac{48(\frac{-2(2 + 0)}{(2x + 1)^{3}})sin(2x + 8lg(2x + 1) + 1)}{ln{10}} - \frac{48*-0sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{2}{10}} - \frac{48cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)^{2}ln{10}} + \frac{384(\frac{-2(2 + 0)}{(2x + 1)^{3}})cos(2x + 8lg(2x + 1) + 1)}{ln^{2}{10}} + \frac{384*-2*0cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{3}{10}} + \frac{384*-sin(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)^{2}ln^{2}{10}}\\=&-12sin(2x + 8lg(2x + 1) + 1) - \frac{288sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln{10}} - \frac{288cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln{10}} - \frac{2304sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{2}{10}} + \frac{192sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln{10}} - \frac{2304cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{2}{10}} - \frac{6144sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{3}{10}}\\\\ &\color{blue}{函数的第 4 阶导数:} \\&\frac{d\left( -12sin(2x + 8lg(2x + 1) + 1) - \frac{288sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln{10}} - \frac{288cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln{10}} - \frac{2304sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{2}{10}} + \frac{192sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln{10}} - \frac{2304cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{2}{10}} - \frac{6144sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{3}{10}}\right)}{dx}\\=&-12cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0) - \frac{288(\frac{-(2 + 0)}{(2x + 1)^{2}})sin(2x + 8lg(2x + 1) + 1)}{ln{10}} - \frac{288*-0sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln^{2}{10}} - \frac{288cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)ln{10}} - \frac{288(\frac{-2(2 + 0)}{(2x + 1)^{3}})cos(2x + 8lg(2x + 1) + 1)}{ln{10}} - \frac{288*-0cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{2}{10}} - \frac{288*-sin(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)^{2}ln{10}} - \frac{2304(\frac{-2(2 + 0)}{(2x + 1)^{3}})sin(2x + 8lg(2x + 1) + 1)}{ln^{2}{10}} - \frac{2304*-2*0sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{3}{10}} - \frac{2304cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)^{2}ln^{2}{10}} + \frac{192(\frac{-3(2 + 0)}{(2x + 1)^{4}})sin(2x + 8lg(2x + 1) + 1)}{ln{10}} + \frac{192*-0sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{2}{10}} + \frac{192cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)^{3}ln{10}} - \frac{2304(\frac{-3(2 + 0)}{(2x + 1)^{4}})cos(2x + 8lg(2x + 1) + 1)}{ln^{2}{10}} - \frac{2304*-2*0cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{3}{10}} - \frac{2304*-sin(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)^{3}ln^{2}{10}} - \frac{6144(\frac{-3(2 + 0)}{(2x + 1)^{4}})sin(2x + 8lg(2x + 1) + 1)}{ln^{3}{10}} - \frac{6144*-3*0sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{4}{10}} - \frac{6144cos(2x + 8lg(2x + 1) + 1)(2 + \frac{8(2 + 0)}{ln{10}(2x + 1)} + 0)}{(2x + 1)^{3}ln^{3}{10}}\\=&-24cos(2x + 8lg(2x + 1) + 1) - \frac{768cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)ln{10}} + \frac{1152sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln{10}} - \frac{9216cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{2}ln^{2}{10}} + \frac{1536cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln{10}} + \frac{18432sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{2}{10}} - \frac{49152cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{3}ln^{3}{10}} - \frac{1152sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{4}ln{10}} + \frac{16896cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{4}ln^{2}{10}} + \frac{73728sin(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{4}ln^{3}{10}} - \frac{98304cos(2x + 8lg(2x + 1) + 1)}{(2x + 1)^{4}ln^{4}{10}}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!