本次共计算 1 个题目:每一题对 x 求 4 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数\frac{x}{({x}^{2} + a)} 关于 x 的 4 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = \frac{x}{(x^{2} + a)}\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( \frac{x}{(x^{2} + a)}\right)}{dx}\\=&(\frac{-(2x + 0)}{(x^{2} + a)^{2}})x + \frac{1}{(x^{2} + a)}\\=&\frac{-2x^{2}}{(x^{2} + a)^{2}} + \frac{1}{(x^{2} + a)}\\\\ &\color{blue}{函数的第 2 阶导数:} \\&\frac{d\left( \frac{-2x^{2}}{(x^{2} + a)^{2}} + \frac{1}{(x^{2} + a)}\right)}{dx}\\=&-2(\frac{-2(2x + 0)}{(x^{2} + a)^{3}})x^{2} - \frac{2*2x}{(x^{2} + a)^{2}} + (\frac{-(2x + 0)}{(x^{2} + a)^{2}})\\=&\frac{8x^{3}}{(x^{2} + a)^{3}} - \frac{6x}{(x^{2} + a)^{2}}\\\\ &\color{blue}{函数的第 3 阶导数:} \\&\frac{d\left( \frac{8x^{3}}{(x^{2} + a)^{3}} - \frac{6x}{(x^{2} + a)^{2}}\right)}{dx}\\=&8(\frac{-3(2x + 0)}{(x^{2} + a)^{4}})x^{3} + \frac{8*3x^{2}}{(x^{2} + a)^{3}} - 6(\frac{-2(2x + 0)}{(x^{2} + a)^{3}})x - \frac{6}{(x^{2} + a)^{2}}\\=&\frac{-48x^{4}}{(x^{2} + a)^{4}} + \frac{48x^{2}}{(x^{2} + a)^{3}} - \frac{6}{(x^{2} + a)^{2}}\\\\ &\color{blue}{函数的第 4 阶导数:} \\&\frac{d\left( \frac{-48x^{4}}{(x^{2} + a)^{4}} + \frac{48x^{2}}{(x^{2} + a)^{3}} - \frac{6}{(x^{2} + a)^{2}}\right)}{dx}\\=&-48(\frac{-4(2x + 0)}{(x^{2} + a)^{5}})x^{4} - \frac{48*4x^{3}}{(x^{2} + a)^{4}} + 48(\frac{-3(2x + 0)}{(x^{2} + a)^{4}})x^{2} + \frac{48*2x}{(x^{2} + a)^{3}} - 6(\frac{-2(2x + 0)}{(x^{2} + a)^{3}})\\=&\frac{384x^{5}}{(x^{2} + a)^{5}} - \frac{480x^{3}}{(x^{2} + a)^{4}} + \frac{120x}{(x^{2} + a)^{3}}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!