本次共计算 1 个题目:每一题对 x 求 2 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数ln(x + \frac{1}{x}) 关于 x 的 2 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( ln(x + \frac{1}{x})\right)}{dx}\\=&\frac{(1 + \frac{-1}{x^{2}})}{(x + \frac{1}{x})}\\=& - \frac{1}{(x + \frac{1}{x})x^{2}} + \frac{1}{(x + \frac{1}{x})}\\\\ &\color{blue}{函数的第 2 阶导数:} \\&\frac{d\left( - \frac{1}{(x + \frac{1}{x})x^{2}} + \frac{1}{(x + \frac{1}{x})}\right)}{dx}\\=& - \frac{(\frac{-(1 + \frac{-1}{x^{2}})}{(x + \frac{1}{x})^{2}})}{x^{2}} - \frac{-2}{(x + \frac{1}{x})x^{3}} + (\frac{-(1 + \frac{-1}{x^{2}})}{(x + \frac{1}{x})^{2}})\\=& - \frac{1}{(x + \frac{1}{x})^{2}x^{4}} + \frac{2}{(x + \frac{1}{x})^{2}x^{2}} + \frac{2}{(x + \frac{1}{x})x^{3}} - \frac{1}{(x + \frac{1}{x})^{2}}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!