本次共计算 1 个题目:每一题对 x 求 2 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数ln(x + {({x}^{2} + 1)}^{\frac{1}{2}}) 关于 x 的 2 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = ln(x + (x^{2} + 1)^{\frac{1}{2}})\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( ln(x + (x^{2} + 1)^{\frac{1}{2}})\right)}{dx}\\=&\frac{(1 + (\frac{\frac{1}{2}(2x + 0)}{(x^{2} + 1)^{\frac{1}{2}}}))}{(x + (x^{2} + 1)^{\frac{1}{2}})}\\=&\frac{x}{(x + (x^{2} + 1)^{\frac{1}{2}})(x^{2} + 1)^{\frac{1}{2}}} + \frac{1}{(x + (x^{2} + 1)^{\frac{1}{2}})}\\\\ &\color{blue}{函数的第 2 阶导数:} \\&\frac{d\left( \frac{x}{(x + (x^{2} + 1)^{\frac{1}{2}})(x^{2} + 1)^{\frac{1}{2}}} + \frac{1}{(x + (x^{2} + 1)^{\frac{1}{2}})}\right)}{dx}\\=&\frac{(\frac{-(1 + (\frac{\frac{1}{2}(2x + 0)}{(x^{2} + 1)^{\frac{1}{2}}}))}{(x + (x^{2} + 1)^{\frac{1}{2}})^{2}})x}{(x^{2} + 1)^{\frac{1}{2}}} + \frac{(\frac{\frac{-1}{2}(2x + 0)}{(x^{2} + 1)^{\frac{3}{2}}})x}{(x + (x^{2} + 1)^{\frac{1}{2}})} + \frac{1}{(x + (x^{2} + 1)^{\frac{1}{2}})(x^{2} + 1)^{\frac{1}{2}}} + (\frac{-(1 + (\frac{\frac{1}{2}(2x + 0)}{(x^{2} + 1)^{\frac{1}{2}}}))}{(x + (x^{2} + 1)^{\frac{1}{2}})^{2}})\\=& - \frac{x^{2}}{(x + (x^{2} + 1)^{\frac{1}{2}})^{2}(x^{2} + 1)} - \frac{2x}{(x + (x^{2} + 1)^{\frac{1}{2}})^{2}(x^{2} + 1)^{\frac{1}{2}}} - \frac{x^{2}}{(x + (x^{2} + 1)^{\frac{1}{2}})(x^{2} + 1)^{\frac{3}{2}}} + \frac{1}{(x + (x^{2} + 1)^{\frac{1}{2}})(x^{2} + 1)^{\frac{1}{2}}} - \frac{1}{(x + (x^{2} + 1)^{\frac{1}{2}})^{2}}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!