本次共计算 1 个题目:每一题对 e 求 1 阶导数。
注意,变量是区分大小写的。\[ \begin{equation}\begin{split}【1/1】求函数(\frac{(w + (1 - e - mp)(b - a))}{(p(1 + e + m - e - mn)(b - p - c - f - e - mp))}) 关于 e 的 1 阶导数:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = \frac{w}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{be}{(-mn + m + 1)(b - p - c - f - e - mp)p} + \frac{ae}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{mb}{(-mn + m + 1)(b - p - c - f - e - mp)} + \frac{ma}{(-mn + m + 1)(b - p - c - f - e - mp)} + \frac{b}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{a}{(-mn + m + 1)(b - p - c - f - e - mp)p}\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( \frac{w}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{be}{(-mn + m + 1)(b - p - c - f - e - mp)p} + \frac{ae}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{mb}{(-mn + m + 1)(b - p - c - f - e - mp)} + \frac{ma}{(-mn + m + 1)(b - p - c - f - e - mp)} + \frac{b}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{a}{(-mn + m + 1)(b - p - c - f - e - mp)p}\right)}{de}\\=&\frac{(\frac{-(0 + 0 + 0)}{(-mn + m + 1)^{2}})w}{(b - p - c - f - e - mp)p} + \frac{(\frac{-(0 + 0 + 0 + 0 - 1 + 0)}{(b - p - c - f - e - mp)^{2}})w}{(-mn + m + 1)p} + 0 - \frac{(\frac{-(0 + 0 + 0)}{(-mn + m + 1)^{2}})be}{(b - p - c - f - e - mp)p} - \frac{(\frac{-(0 + 0 + 0 + 0 - 1 + 0)}{(b - p - c - f - e - mp)^{2}})be}{(-mn + m + 1)p} - \frac{b}{(-mn + m + 1)(b - p - c - f - e - mp)p} + \frac{(\frac{-(0 + 0 + 0)}{(-mn + m + 1)^{2}})ae}{(b - p - c - f - e - mp)p} + \frac{(\frac{-(0 + 0 + 0 + 0 - 1 + 0)}{(b - p - c - f - e - mp)^{2}})ae}{(-mn + m + 1)p} + \frac{a}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{(\frac{-(0 + 0 + 0)}{(-mn + m + 1)^{2}})mb}{(b - p - c - f - e - mp)} - \frac{(\frac{-(0 + 0 + 0 + 0 - 1 + 0)}{(b - p - c - f - e - mp)^{2}})mb}{(-mn + m + 1)} + 0 + \frac{(\frac{-(0 + 0 + 0)}{(-mn + m + 1)^{2}})ma}{(b - p - c - f - e - mp)} + \frac{(\frac{-(0 + 0 + 0 + 0 - 1 + 0)}{(b - p - c - f - e - mp)^{2}})ma}{(-mn + m + 1)} + 0 + \frac{(\frac{-(0 + 0 + 0)}{(-mn + m + 1)^{2}})b}{(b - p - c - f - e - mp)p} + \frac{(\frac{-(0 + 0 + 0 + 0 - 1 + 0)}{(b - p - c - f - e - mp)^{2}})b}{(-mn + m + 1)p} + 0 - \frac{(\frac{-(0 + 0 + 0)}{(-mn + m + 1)^{2}})a}{(b - p - c - f - e - mp)p} - \frac{(\frac{-(0 + 0 + 0 + 0 - 1 + 0)}{(b - p - c - f - e - mp)^{2}})a}{(-mn + m + 1)p} + 0\\=&\frac{w}{(b - p - c - f - e - mp)^{2}(-mn + m + 1)p} - \frac{be}{(b - p - c - f - e - mp)^{2}(-mn + m + 1)p} - \frac{b}{(-mn + m + 1)(b - p - c - f - e - mp)p} + \frac{ae}{(b - p - c - f - e - mp)^{2}(-mn + m + 1)p} + \frac{a}{(-mn + m + 1)(b - p - c - f - e - mp)p} - \frac{mb}{(b - p - c - f - e - mp)^{2}(-mn + m + 1)} + \frac{ma}{(b - p - c - f - e - mp)^{2}(-mn + m + 1)} + \frac{b}{(b - p - c - f - e - mp)^{2}(-mn + m + 1)p} - \frac{a}{(b - p - c - f - e - mp)^{2}(-mn + m + 1)p}\\ \end{split}\end{equation} \]你的问题在这里没有得到解决?请到 热门难题 里面看看吧!