在线解一元方程：
直接输入任意的一元方程，然后点击“下一步”按钮，即可获得方程的解。
它支持包含数学函数的方程。
直接输入任意的一元方程，然后点击“下一步”按钮，即可获得方程的解。
它支持包含数学函数的方程。
总述：本次共解1题。其中
☆方程1题
〖 1/1方程〗
作业：求方程 0 = -40.03/(1+(x/12))+42.73/((1+(x/2)) ) 的解.
题型：方程
解:原方程：
| 0 | = | - | 4003 100 | ÷ | ( | 1 | + | ( | x | ÷ | 12 | ) | ) | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 方程两边同时乘以： | ( | 1 | + | ( | x | ÷ | 12 | ) | ) |
| 0 | = | - | 4003 100 | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | × | ( | 1 | + | ( | x | ÷ | 12 | ) | ) |
| 0 | = | - | 4003 100 | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | × | 1 | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | × | ( | x | ÷ | 12 | ) |
| 0 | = | - | 4003 100 | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | × | ( | x | ÷ | 12 | ) |
| 方程两边同时乘以： | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | × | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | + | 4273 100 | + | 4273 100 | ÷ | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | × | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 方程两边同时乘以： | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | × | 1 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | − | 4003 100 | ( | x | ÷ | 2 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | − | 4003 100 | ( | x | ÷ | 2 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | − | 4003 100 | ( | x | ÷ | 2 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | × | 1 | − | 4003 100 | ( | x | ÷ | 2 | ) | − | 4003 100 | ( | x | ÷ | 2 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 100 | ( | x | ÷ | 2 | ) | − | 4003 100 | ( | x | ÷ | 2 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 100 | x | ÷ | 2 | − | 4003 100 | ( | x | ÷ | 2 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 200 | x | − | 4003 100 | ( | x | ÷ | 2 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 200 | x | − | 4003 100 | x | ÷ | 2 | × | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 200 | x | − | 4003 200 | x | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 200 | x | − | 4003 200 | x | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 200 | x | − | 4003 200 | x | × | 1 | − | 4003 200 | x | ( | x | ÷ | 2 | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 |
| 0 | = | - | 4003 100 | − | 4003 200 | x | − | 4003 200 | x | − | 4003 200 | x | ( | x | ÷ | 2 | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) |
| 0 | = | - | 4003 100 | − | 4003 100 | x | − | 4003 200 | x | ( | x | ÷ | 2 | ) | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 100 | x | − | 4003 200 | x | x | ÷ | 2 | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 100 | x | − | 4003 400 | x | x | + | 4273 100 | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 100 | x | − | 4003 400 | x | x | + | 4273 100 | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | + | 4273 100 | ( | x | ÷ | 12 | ) | ( | ( | 1 | + | ( | x | ÷ | 2 | ) | ) | ) |
| 0 | = | - | 4003 100 | − | 4003 100 | x | − | 4003 400 | x | x | + | 4273 100 | × | 1 | + | 4273 100 | ( | x | ÷ | 2 | ) | + | 4273 100 | ( | x | ÷ | 12 | ) |
x≈0.164092 ，保留6位小数
有 1个解。
解一元一次方程的详细方法请参阅：《一元一次方程的解法》
你的问题在这里没有得到解决？请到 热门难题 里面看看吧！
最 新 发 布
新增加身体健康评估计算器，位置：“数学运算 > 身体健康评估”。
新增加学习笔记(安卓版)百度网盘快速下载应用程序，欢迎使用。
新增加学习笔记(安卓版)本站下载应用程序，欢迎使用。
新增线性代数行列式的计算，欢迎使用。
数学计算和一元方程已经支持正割函数和余割函数，欢迎使用。
新增加贷款计算器模块（具体位置：数学运算 > 贷款计算器），欢迎使用。