Mathematics
         
语言：中文    Language:English
                                Equations   
Fold
                                Unary equation
                                Multivariate equation
                                Math OP  
Unfold
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
On line solution of multivariate equations：
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location：Equations > Multivariate equations > Answer
detailed information：
The input equation set is:
 A + D = -13    (1)
 B + E = -3    (2)
 C + F = 3    (3)
 B + D = 0    (4)
 C + E = 0    (5)
0 = 0    (6)
Question solving process:

Subtract both sides of equation (2) from both sides of equation (4) ,the equations are reduced to:
 A + D = -13    (1)
 B + E = -3    (2)
 C + F = 3    (3)
 D -1E = 3    (4)
 C + E = 0    (5)
0 = 0    (6)

Subtract both sides of equation (3) from both sides of equation (5) ,the equations are reduced to:
 A + D = -13    (1)
 B + E = -3    (2)
 C + F = 3    (3)
 D -1E = 3    (4)
 E -1F = -3    (5)
0 = 0    (6)

Add both sides of equation (5) to both sides of equation (4), get the equation：
 A + D = -13    (1)
 B + E = -3    (2)
 C + F = 3    (3)
 D -1F = 0    (4)
 E -1F = -3    (5)
0 = 0    (6)

Subtract both sides of equation (5) from both sides of equation (2), get the equation：
 A + D = -13    (1)
 B + F = 0    (2)
 C + F = 3    (3)
 D -1F = 0    (4)
 E -1F = -3    (5)
0 = 0    (6)

Subtract both sides of equation (4) from both sides of equation (1), get the equation：
 A + F = -13    (1)
 B + F = 0    (2)
 C + F = 3    (3)
 D -1F = 0    (4)
 E -1F = -3    (5)
0 = 0    (6)


Therefore, the solution of the equation set is:
A = -13 - 1F
B = -1F
C = 3 - 1F
D = 1F
E = -3 + 1F

Where:  F are arbitrary constants.
解方程组的详细方法请参阅：《多元一次方程组的解法》
return



  New addition:Lenders ToolBox module（Specific location：Math OP > Lenders ToolBox ），welcome。