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On line solution of multivariate equations：
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location：Equations > Multivariate equations > Answer
detailed information：
The input equation set is:
 
27363
5000
A = 0    (1)
 
97863
5000
A = 0    (2)
 
12393
250
A = 0    (3)
 
5893
250
A = 0    (4)
 7A = 0    (5)
0 = 0    (6)
Question solving process:

Multiply both sides of equation (1) by 32621
Divide the two sides of equation (1) by 9121, the equation can be obtained:
         
97863
5000
A = 0    (7)
, then subtract both sides of equation (7) from both sides of equation (2), the equations are reduced to:
 
27363
5000
A = 0    (1)
0 = 0    (2)
 
12393
250
A = 0    (3)
 
5893
250
A = 0    (4)
 7A = 0    (5)
0 = 0    (6)

Multiply both sides of equation (1) by 82620
Divide the two sides of equation (1) by 9121, the equation can be obtained:
         
16148079
325750
A = 0    (8)
, then subtract both sides of equation (8) from both sides of equation (3), the equations are reduced to:
 
27363
5000
A = 0    (1)
0 = 0    (2)
0 = 0    (3)
 
5893
250
A = 0    (4)
 7A = 0    (5)
0 = 0    (6)

Multiply both sides of equation (1) by 117860
Divide the two sides of equation (1) by 27363, the equation can be obtained:
         
7678579
325750
A = 0    (9)
, then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
 
27363
5000
A = 0    (1)
0 = 0    (2)
0 = 0    (3)
0 = 0    (4)
 7A = 0    (5)
0 = 0    (6)

Multiply both sides of equation (1) by 5000
Divide the two sides of equation (1) by 3909, the equation can be obtained:
         
9121
1303
A = 0    (10)
, then subtract both sides of equation (10) from both sides of equation (5), the equations are reduced to:
 
27363
5000
A = 0    (1)
0 = 0    (2)
0 = 0    (3)
0 = 0    (4)
0 = 0    (5)
0 = 0    (6)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to：
 A = 0    (1)
0 = 0    (2)
0 = 0    (3)
0 = 0    (4)
0 = 0    (5)
0 = 0    (6)


Therefore, the solution of the equation set is:
A = 0

Where:  B, C, D, E, F are arbitrary constants.
解方程组的详细方法请参阅：《多元一次方程组的解法》
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