Mathematics
         
语言:中文    Language:English
On line solution of multivariate equations:
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location:Equations > Multivariate equations > Answer
detailed information:
The input equation set is:
 19A -5B -4C = 0    (1)
-5A + 25B -20C = 50    (2)
-4A -20B + 24C -15D = 0    (3)
0 = 0    (4)
Question solving process:

Multiply both sides of equation (1) by 5
Divide the two sides of equation (1) by 19, the equation can be obtained:
         5A 
25
19
B 
20
19
C = 0    (5)
, then add the two sides of equation (5) to both sides of equation (2), the equations are reduced to:
 19A -5B -4C = 0    (1)
 
450
19
B 
400
19
C = 50    (2)
-4A -20B + 24C -15D = 0    (3)
0 = 0    (4)

Multiply both sides of equation (1) by 4
Divide the two sides of equation (1) by 19, the equation can be obtained:
         4A 
20
19
B 
16
19
C = 0    (6)
, then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
 19A -5B -4C = 0    (1)
 
450
19
B 
400
19
C = 50    (2)
400
19
B + 
440
19
C -15D = 0    (3)
0 = 0    (4)

Multiply both sides of equation (2) by 8
Divide the two sides of equation (2) by 9, the equation can be obtained:
         
400
19
B 
3200
171
C = 
400
9
    (7)
, then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
 19A -5B -4C = 0    (1)
 
450
19
B 
400
19
C = 50    (2)
 
760
171
C -15D = 
7600
171
    (3)
0 = 0    (4)

Multiply both sides of equation (3) by 90
Divide both sides of equation (3) by 19, get the equation:
         
400
19
C 
1350
19
D = 
4000
19
    (8)
, then add the two sides of equation (8) to both sides of equation (2), get the equation:
 19A -5B -4C = 0    (1)
 
450
19
B 
1350
19
D = 
4950
19
    (2)
 
760
171
C -15D = 
7600
171
    (3)
0 = 0    (4)

Multiply both sides of equation (3) by 171
Divide both sides of equation (3) by 190, get the equation:
         4C 
27
2
D = 40    (9)
, then add the two sides of equation (9) to both sides of equation (1), get the equation:
 19A -5B 
27
2
D = 40    (1)
 
450
19
B 
1350
19
D = 
4950
19
    (2)
 
760
171
C -15D = 
7600
171
    (3)
0 = 0    (4)

Multiply both sides of equation (2) by 19
Divide both sides of equation (2) by 90, get the equation:
         5B -15D = 55    (10)
, then add the two sides of equation (10) to both sides of equation (1), get the equation:
 19A 
57
2
D = 95    (1)
 
450
19
B 
1350
19
D = 
4950
19
    (2)
 C 
513
152
D = 10    (3)
0 = 0    (4)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
 A 
3
2
D = 5    (1)
 B -3D = 11    (2)
 C 
513
152
D = 10    (3)
0 = 0    (4)


Therefore, the solution of the equation set is:
A = 5 + 
3
2
D
B = 11 + 3D
C = 10 + 
513
152
D

Where:  D are arbitrary constants.
解方程组的详细方法请参阅:《多元一次方程组的解法》







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