detailed information: The input equation set is:
| | | | | -4 | A | | -20 | B | + | | 24 | C | | -15 | D | = | | 0 | | (3) |
| | Question solving process:
Multiply both sides of equation (1) by 5 Divide the two sides of equation (1) by 19, the equation can be obtained: | | 5 | A | | - | 25 19 | B | | - | 20 19 | C | = | | 0 | (5) | , then add the two sides of equation (5) to both sides of equation (2), the equations are reduced to:
| | | | | -4 | A | | -20 | B | + | | 24 | C | | -15 | D | = | | 0 | | (3) |
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Multiply both sides of equation (1) by 4 Divide the two sides of equation (1) by 19, the equation can be obtained: | | 4 | A | | - | 20 19 | B | | - | 16 19 | C | = | | 0 | (6) | , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
| | | | | - | 400 19 | B | + | | | 440 19 | C | | -15 | D | = | | 0 | | (3) |
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Multiply both sides of equation (2) by 8 Divide the two sides of equation (2) by 9, the equation can be obtained: | | | 400 19 | B | | - | 3200 171 | C | = | | | 400 9 | (7) | , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
| | | | | | | 760 171 | C | | -15 | D | = | | | 7600 171 | | (3) |
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Multiply both sides of equation (3) by 90 Divide both sides of equation (3) by 19, get the equation: | | | 400 19 | C | | - | 1350 19 | D | = | | | 4000 19 | (8) | , then add the two sides of equation (8) to both sides of equation (2), get the equation:
| | | | | | 450 19 | B | | - | 1350 19 | D | = | | | 4950 19 | | (2) |
| | | 760 171 | C | | -15 | D | = | | | 7600 171 | | (3) |
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Multiply both sides of equation (3) by 171 Divide both sides of equation (3) by 190, get the equation:, then add the two sides of equation (9) to both sides of equation (1), get the equation:
| | | | | | 450 19 | B | | - | 1350 19 | D | = | | | 4950 19 | | (2) |
| | | 760 171 | C | | -15 | D | = | | | 7600 171 | | (3) |
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Multiply both sides of equation (2) by 19 Divide both sides of equation (2) by 90, get the equation:, then add the two sides of equation (10) to both sides of equation (1), get the equation:
| | | | | | 450 19 | B | | - | 1350 19 | D | = | | | 4950 19 | | (2) |
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The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Where: D are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |