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〖1/1算式〗
    作业：求算式 2*500/sqrt(3)-350-350*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1) 的值.
    题型：数学计算
    解:
          2*500/sqrt(3)-350-350*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1)
        =2*500/sqrt3-350-350*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1)
        =2*500/sqrt3-350-350*0.05^2/0.0075*((0.1^2/0.05^2)+1)
        =2*500/sqrt3-350-350*0.05^2/0.0075*(4+1)
        =2*500/sqrt3-350-350*0.05^2/0.0075*5
        =2*500/1.732051-350-350*0.05^2/0.0075*5

        =2*500/1.732051-350-350*0.0025/0.0075*5
        =1000/1.732051-350-350*0.0025/0.0075*5
        =577.350205-350-350*0.0025/0.0075*5
        =577.350205-350-0.875/0.0075*5
        =577.350205-350-116.666667*5
        =577.350205-350-583.333335
        =227.350205-583.333335
        =-355.98313
    答案:2*500/sqrt(3)-350-350*0.05^2/(0.1^2-0.05^2)*((0.1^2/0.05^2)+1)=-355.98313

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