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当前位置:求导函数 > 导函数计算历史 > 答案
    本次共计算 1 个题目:每一题对 x 求 1 阶导数。
    注意,变量是区分大小写的。
\[ \begin{equation}\begin{split}【1/1】求函数({(\frac{1}{2}x)}^{(\frac{x}{(1 - x)})}){(1 - a)}^{(\frac{\frac{3}{2}x}{(\frac{1}{2}(1 - x))})} 关于 x 的 1 阶导数:\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = (\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}\\&\color{blue}{函数的第 1 阶导数:}\\&\frac{d\left( (\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}\right)}{dx}\\=&((\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}(((\frac{-(-1 + 0)}{(-x + 1)^{2}})x + \frac{1}{(-x + 1)})ln(\frac{1}{2}x) + \frac{(\frac{x}{(-x + 1)})(\frac{1}{2})}{(\frac{1}{2}x)}))(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})} + (\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}((-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}((\frac{3}{2}(\frac{-(\frac{-1}{2} + 0)}{(\frac{-1}{2}x + \frac{1}{2})^{2}})x + \frac{\frac{3}{2}}{(\frac{-1}{2}x + \frac{1}{2})})ln(-a + 1) + \frac{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})(0 + 0)}{(-a + 1)}))\\=&\frac{x(\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}ln(\frac{1}{2}x)}{(-x + 1)^{2}} + \frac{(\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}ln(\frac{1}{2}x)}{(-x + 1)} + \frac{3(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}(\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}ln(-a + 1)}{2(\frac{-1}{2}x + \frac{1}{2})} + \frac{3x(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}(\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}ln(-a + 1)}{4(\frac{-1}{2}x + \frac{1}{2})^{2}} + \frac{(\frac{1}{2}x)^{(\frac{x}{(-x + 1)})}(-a + 1)^{(\frac{\frac{3}{2}x}{(\frac{-1}{2}x + \frac{1}{2})})}}{(-x + 1)}\\ \end{split}\end{equation} \]





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