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〖1/1算式〗
作业:求算式 2.24/(1.0224)+2.24/((1.0224)^2)+102.24/((1.0224)^3) 的值.
题型:数学计算
解:
2.24/(1.0224)+2.24/((1.0224)^2)+102.24/((1.0224)^3)
=2.24/1.0224+2.24/((1.0224)^2)+102.24/((1.0224)^3)
=2.24/1.0224+2.24/(1.0224^2)+102.24/((1.0224)^3)
=2.24/1.0224+2.24/1.04530176+102.24/((1.0224)^3)
=2.24/1.0224+2.24/1.04530176+102.24/(1.0224^3)
=2.24/1.0224+2.24/1.04530176+102.24/1.068716519424
=2.190923+2.24/1.04530176+102.24/1.068716519424
=2.190923+2.142922+102.24/1.068716519424
=2.190923+2.142922+95.666155
=4.333845+95.666155
=100 答案:2.24/(1.0224)+2.24/((1.0224)^2)+102.24/((1.0224)^3)=100你的问题在这里没有得到解决?请到 热门难题 里面看看吧!