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〖1/1算式〗
作业:求算式 0.3*14.3*1000*0.785*(1-(sin(2*3.14159*0.3)/(2*3.14159*0.3)))+(3*0.3-1.25)*300*25445/1000 的值.
题型:数学计算
解:
0.3*14.3*1000*0.785*(1-(sin(2*3.14159*0.3)/(2*3.14159*0.3)))+(3*0.3-1.25)*300*25445/1000
=0.3*14.3*1000*0.785*(1-(sin1.884954/(2*3.14159*0.3)))+(3*0.3-1.25)*300*25445/1000
=0.3*14.3*1000*0.785*(1-(sin1.884954/1.884954))+(3*0.3-1.25)*300*25445/1000
=0.3*14.3*1000*0.785*(1-0.504552)+(3*0.3-1.25)*300*25445/1000
=0.3*14.3*1000*0.785*0.495448+(3*0.3-1.25)*300*25445/1000
=0.3*14.3*1000*0.785*0.495448+(-0.35)*300*25445/1000
=4.29*1000*0.785*0.495448+(-0.35)*300*25445/1000
=4290*0.785*0.495448+(-0.35)*300*25445/1000
=3367.65*0.495448+(-0.35)*300*25445/1000
=1668.495457+(-0.35)*300*25445/1000
=1668.495457+(-105)*25445/1000
=1668.495457+(-2671725)/1000
=1668.495457+(-2671.725)
=-1003.229543 答案:0.3*14.3*1000*0.785*(1-(sin(2*3.14159*0.3)/(2*3.14159*0.3)))+(3*0.3-1.25)*300*25445/1000=-1003.229543 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!