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〖1/1算式〗
作业:求算式 2.7*1.43*0.5*(1-(sin(2*3.14159*2.7))/(2*3.14159*2.7))+(3*2.7-1.25)*270*3848 的值.
题型:数学计算
解:
2.7*1.43*0.5*(1-(sin(2*3.14159*2.7))/(2*3.14159*2.7))+(3*2.7-1.25)*270*3848
=2.7*1.43*0.5*(1-(sin16.964586)/(2*3.14159*2.7))+(3*2.7-1.25)*270*3848
=2.7*1.43*0.5*(1-(-0.951052)/(2*3.14159*2.7))+(3*2.7-1.25)*270*3848
=2.7*1.43*0.5*(1-(-0.951052)/16.964586)+(3*2.7-1.25)*270*3848
=2.7*1.43*0.5*1.056061+(3*2.7-1.25)*270*3848
=2.7*1.43*0.5*1.056061+6.85*270*3848
=3.861*0.5*1.056061+6.85*270*3848
=1.9305*1.056061+6.85*270*3848
=2.038726+6.85*270*3848
=2.038726+1849.5*3848
=2.038726+7116876
=7116878.038726 答案:2.7*1.43*0.5*(1-(sin(2*3.14159*2.7))/(2*3.14159*2.7))+(3*2.7-1.25)*270*3848=7116878.038726 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!