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☆算术计算1题
〖1/1算式〗
作业:求算式 arctan(2/2)+arctan(2/6)-arctan(2/12)-arctan(2/60)-arctan(2/80) 的值.
题型:数学计算
解:
arctan(2/2)+arctan(2/6)-arctan(2/12)-arctan(2/60)-arctan(2/80)
=arctan1+arctan(2/6)-arctan(2/12)-arctan(2/60)-arctan(2/80)
=arctan1+arctan0.333333-arctan(2/12)-arctan(2/60)-arctan(2/80)
=arctan1+arctan0.333333-arctan0.166667-arctan(2/60)-arctan(2/80)
=arctan1+arctan0.333333-arctan0.166667-arctan0.033333-arctan(2/80)
=arctan1+arctan0.333333-arctan0.166667-arctan0.033333-arctan0.025
=0.785398+arctan0.333333-arctan0.166667-arctan0.033333-arctan0.025
=0.785398+0.32175-arctan0.166667-arctan0.033333-arctan0.025
=0.785398+0.32175-0.165149-arctan0.033333-arctan0.025
=0.785398+0.32175-0.165149-0.033321-arctan0.025
=0.785398+0.32175-0.165149-0.033321-0.024995
=1.107148-0.165149-0.033321-0.024995
=0.941999-0.033321-0.024995
=0.908678-0.024995
=0.883683 答案:arctan(2/2)+arctan(2/6)-arctan(2/12)-arctan(2/60)-arctan(2/80)=0.883683 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!