总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((90+80+70.0)/2907.9×10^3+20)/(600-35))×((8000/600))^2×0.89 的值.
题型:数学计算
解:
1+1/(1300×((90+80+70.0)/2907.9×10^3+20)/(600-35))×((8000/600))^2×0.89
=1+1/(1300×(240/2907.9×10^3+20)/(600-35))×((8000/600))^2×0.89
=1+1/(1300×102.534/(600-35))×((8000/600))^2×0.89
=1+1/(1300×102.534/565)×((8000/600))^2×0.89
=1+1/235.918938×((8000/600))^2×0.89
=1+1/235.918938×(13.333333)^2×0.89
=1+1/235.918938×13.333333^2×0.89
=1+1/235.918938×177.777768888889×0.89
=1+0.004239×177.777768888889×0.89
=1+0.7536×0.89
=1+0.670704
=1.670704 答案:1+1/(1300×((90+80+70.0)/2907.9×10^3+20)/(600-35))×((8000/600))^2×0.89=1.670704你的问题在这里没有得到解决?请到 热门难题 里面看看吧!