总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((80.39+61.25+38.14)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1 的值.
题型:数学计算
解:
1+1/(1300×((80.39+61.25+38.14)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1
=1+1/(1300×(179.78/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1
=1+1/(1300×122.287/(700-35))×((7000/700))^2×1
=1+1/(1300×122.287/665)×((7000/700))^2×1
=1+1/239.057293×((7000/700))^2×1
=1+1/239.057293×(10)^2×1
=1+1/239.057293×10^2×1
=1+1/239.057293×100×1
=1+0.004183×100×1
=1+0.4183×1
=1+0.4183
=1.4183 答案:1+1/(1300×((80.39+61.25+38.14)/1816.2×10^3+23.3)/(700-35))×((7000/700))^2×1=1.4183你的问题在这里没有得到解决?请到 热门难题 里面看看吧!