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〖1/1算式〗
作业:求算式 (2*(3.3^2-3.2^2))/(2*151.85)+2*(3.3-3.2)/(161.55+0.44*33)*33 的值.
题型:数学计算
解:
(2*(3.3^2-3.2^2))/(2*151.85)+2*(3.3-3.2)/(161.55+0.44*33)*33
=(2*0.65)/(2*151.85)+2*(3.3-3.2)/(161.55+0.44*33)*33
=1.3/(2*151.85)+2*(3.3-3.2)/(161.55+0.44*33)*33
=1.3/303.7+2*(3.3-3.2)/(161.55+0.44*33)*33
=1.3/303.7+2*0.1/(161.55+0.44*33)*33
=1.3/303.7+2*0.1/176.07*33
=0.004281+2*0.1/176.07*33
=0.004281+0.2/176.07*33
=0.004281+0.001136*33
=0.004281+0.037488
=0.041769 答案:(2*(3.3^2-3.2^2))/(2*151.85)+2*(3.3-3.2)/(161.55+0.44*33)*33=0.041769你的问题在这里没有得到解决?请到 热门难题 里面看看吧!