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〖1/1算式〗
作业:求算式 3*10^(-4)*((73.9^2-3.3^2)/40.4)+2.16*10^(-7)*(73.9-3.3)*33/0.8 的值.
题型:数学计算
解:
3*10^(-4)*((73.9^2-3.3^2)/40.4)+2.16*10^(-7)*(73.9-3.3)*33/0.8
=3*10^(-4)*((73.9^2-3.3^2)/40.4)+2.16*10^(-7)*(73.9-3.3)*33/0.8
=3*10^-4*(5450.32/40.4)+2.16*10^(-7)*(73.9-3.3)*33/0.8
=3*10^-4*134.908911+2.16*10^(-7)*(73.9-3.3)*33/0.8
=3*10^-4*134.908911+2.16*10^(-7)*(73.9-3.3)*33/0.8
=3*10^-4*134.908911+2.16*10^-7*70.6*33/0.8
=3*0.0001*134.908911+2.16*10^(-7)*70.6*33/0.8
=3*0.0001*134.908911+2.16*0.0000001*70.6*33/0.8
=0.0003*134.908911+2.16*0.0000001*70.6*33/0.8
=0.040473+2.16*0.0000001*70.6*33/0.8
=0.040473+0*70.6*33/0.8
=0.040473+0*33/0.8
=0.040473+0/0.8
=0.040473+0
=0.040473 答案:3*10^(-4)*((73.9^2-3.3^2)/40.4)+2.16*10^(-7)*(73.9-3.3)*33/0.8=0.040473你的问题在这里没有得到解决?请到 热门难题 里面看看吧!