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〖1/1算式〗
作业:求算式 (2*10^(-2)*(4.05^2-3.2^2))/(2*151.85)+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33) 的值.
题型:数学计算
解:
(2*10^(-2)*(4.05^2-3.2^2))/(2*151.85)+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33)
=(2*10^(-2)*(4.05^2-3.2^2))/(2*151.85)+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33)
=(2*10^-2*6.1625)/(2*151.85)+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33)
=0.12325/(2*151.85)+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33)
=0.12325/303.7+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33)
=0.12325/303.7+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33)
=0.12325/303.7+2*10^-2*(0.85/(161.55+0.44*33)*33)
=0.12325/303.7+2*10^-2*(0.85/176.07*33)
=0.12325/303.7+2*10^-2*0.159324
=0.12325/303.7+2*0.01*0.159324
=0.000406+2*0.01*0.159324
=0.000406+0.02*0.159324
=0.000406+0.003186
=0.003592 答案:(2*10^(-2)*(4.05^2-3.2^2))/(2*151.85)+2*10^(-2)*((4.05-3.2)/(161.55+0.44*33)*33)=0.003592你的问题在这里没有得到解决?请到 热门难题 里面看看吧!