总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 1/12×(0.85)^2×((2×2.8+0.9)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8) 的值.
    题型：数学计算
    解:
          1/12×(0.85)^2×((2×2.8+0.9)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.85^2×((2×2.8+0.9)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.85^2×(6.5*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.85^2×(6.5*(64-174.72/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.85^2×(6.5*(64-174.72/6.72)+(32-24.7)×2.8)
        =1/12×0.85^2×(6.5*38+(32-24.7)×2.8)
        =1/12×0.85^2×(6.5*38+7.3×2.8)
        =1/12×0.85^2×267.44
        =1/12×0.7225×267.44
        =0.083333×0.7225×267.44
        =0.060208×267.44
        =16.102028
    答案:1/12×(0.85)^2×((2×2.8+0.9)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)=16.102028

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