总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 1/12×(0.75)^2×((2×2.8+0.7)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8) 的值.
    题型：数学计算
    解:
          1/12×(0.75)^2×((2×2.8+0.7)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.75^2×((2×2.8+0.7)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.75^2×(6.3*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.75^2×(6.3*(64-174.72/(2.8×2.4))+(32-24.7)×2.8)
        =1/12×0.75^2×(6.3*(64-174.72/6.72)+(32-24.7)×2.8)
        =1/12×0.75^2×(6.3*38+(32-24.7)×2.8)
        =1/12×0.75^2×(6.3*38+7.3×2.8)
        =1/12×0.75^2×259.84
        =1/12×0.5625×259.84
        =0.083333×0.5625×259.84
        =0.046875×259.84
        =12.18
    答案:1/12×(0.75)^2×((2×2.8+0.7)*(64-(2×2.8×2.4×0.5×26)/(2.8×2.4))+(32-24.7)×2.8)=12.18

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